python-两个字典对比删除重复的键值
代码:
new = {'k1':1,'k2':2,'k3':3}
old = {'k1':1,'k2':4,'k3':3}
for i in list(new):
if new[i] == old[i]:
new.pop(i)
print(new)
输出:
{'k2': 2}
是不是很简单,看似简单的代码用处非常大哦,自己体会吧
代码:
new = {'k1':1,'k2':2,'k3':3}
old = {'k1':1,'k2':4,'k3':3}
for i in list(new):
if new[i] == old[i]:
new.pop(i)
print(new)
输出:
{'k2': 2}
是不是很简单,看似简单的代码用处非常大哦,自己体会吧